September 2021 0 19 Report
Прямоугольный параллелепипед ABCDA1B1C1D1 подобен прямоугольному параллелепипеду MNKLM1N1K1L1 с коэффициентом подобия 2. Чему равен объём прямоугольного параллелепипеда MNKLM1N1K1L1, если AB = 3/5 дм, AB = 2 1/2 дм и AA1 = 2 дм?
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
x python 1 abs x 2 sqr x 3 sqrt x 4 int x
Answer
python 1 int 2 float 3 str 4 bool
Answer
python 1 2 3 4 639f18c805134
Answer
100 1000 python
Answer
python python 638b4c20124c1
Answer
1 if b 0 print 2 if a lt b min a else min
Answer
python 638747402ed67
Answer
python 1 integer 2
Answer
python python
Answer
python 637c2e93a2bf8
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.