2, если 270

Wedma1999 @Wedma1999

July 2022 1 12 Report

Вычислите sin a/2, cos a/2 и tg a/2, если 270<а<360 и sin = -0,8.

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$\dispaystyle 270\ \textless \ \alpha \ \textless \ 360\\ \frac{3\pi }{2}\ \textless \ \alpha \ \textless \ 2 \pi$

значит cos a>0

$\dispaystyle \frac{3\pi }{2}\ \textless \ \alpha \ \textless \ 2 \pi \\ \frac{3 \pi }{4}\ \textless \ \frac{ \alpha }{2}\ \textless \ \pi$

Значит cos(a/2)<0; sin(a/2)>0; tg(a/2)<0

$\dispaystyle sin a=-0.8\\cos^2a+sin^2a=1\\cosa= \sqrt{1-sin^2a}\\cosa= \sqrt{1-(-0.8)^2}= \sqrt{1-0.64}= \sqrt{0.36}=0.6$

$\dispaystyle sin \frac{a}{2}= \sqrt{ \frac{1-cosa}{2}}\\cos \frac{a}{2}= \sqrt{ \frac{1+cosa}{2}}\\tg \frac{a}{2}= \sqrt{ \frac{1-cosa}{1+cosa}}$

$\dispaystyle sin \frac{a}{2}= \sqrt{ \frac{1-0.6}{2}}= \sqrt{ \frac{0.4}{2}}= \sqrt{0.2}$

$\dispaystyle cos \frac{a}{2}=- \sqrt{ \frac{1+0.6}{2}}=- \sqrt{ \frac{1.6}{2}}=- \sqrt{0.8}$

$\dispaystyle tg \frac{a}{2}=-\sqrt{ \frac{1-0.6}{1+0.6}}=-\sqrt{ \frac{0.4}{1.6}}=- \sqrt{0.25}=-0.5$

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