2) (х – 5)^2 – (х + 5)2 = 20
3) (х – 2)(х^2 + 2х + 4) = х(х – 1)2 + 2х2
4) 2х(2х – 1) = 3х^2 – (3 – х)(3+х)
5) (х + 1)^2 = 3х + 1
помогите пж
3) (х – 2)(х^2 + 2х + 4) = х(х – 1)2 + 2х2
4) 2х(2х – 1) = 3х^2 – (3 – х)(3+х)
5) (х + 1)^2 = 3х + 1
помогите пж
Answers & Comments
ответ:5)x1=0;x2=1
x^2+2x+1=3x+1
x^2-x=0
x(x-1)=0
x1=0
x2=1