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maslinnikovaan2
@maslinnikovaan2
July 2022
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(2-х)^2-x(x+3)=18 решите уравнение
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Marina2001m
2^x + 2^(x-3) = 18
2^x (1+2^(-3)) = 18
2^x (1+1/8) = 18
2^x * 9/8 = 18
2^x = 18*8/9
2^x = 16
2^x = 2^4
x = 4
1 votes
Thanks 2
Shelkovaia
4-4х+х^2-х^2-3х=18
-7х=18-4
-7х=14
х=-2
1 votes
Thanks 1
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Answers & Comments
2^x (1+2^(-3)) = 18
2^x (1+1/8) = 18
2^x * 9/8 = 18
2^x = 18*8/9
2^x = 16
2^x = 2^4
x = 4
-7х=18-4
-7х=14
х=-2