Ответ:
2x=7π/6 2x=11π/6
2x=7π/6+2kπ, k∈Z 2x=11π/6+2kπ, k∈Z
x=7π/12+kπ, k∈Z x=11π/12+kπ, k∈Z
Объяснение:
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Ответ:
2x=7π/6 2x=11π/6
2x=7π/6+2kπ, k∈Z 2x=11π/6+2kπ, k∈Z
x=7π/12+kπ, k∈Z x=11π/12+kπ, k∈Z
Объяснение: