Найдите сумму первых шести членов геометрической прогрессии 1/8, 1/4, 1/2....., и поясните, пожалуйста.
b1=1/8
b2=1/4
q=b2/b1= (1/4)/(1/8)=2
S6= (1/8( 2^6-1))/(2-1) = 1/8 *63 =7.875
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b1=1/8
b2=1/4
q=b2/b1= (1/4)/(1/8)=2
S6= (1/8( 2^6-1))/(2-1) = 1/8 *63 =7.875