y=√(8-x²/2)
8-x²/2≥0
(16-x²)/2≥0
16-x²≥0
(4-х)*(4+х)≥0
____-4_______4______
- + -
Область определения х∈[-4;4]
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Verified answer
y=√(8-x²/2)
8-x²/2≥0
(16-x²)/2≥0
16-x²≥0
(4-х)*(4+х)≥0
____-4_______4______
- + -
Область определения х∈[-4;4]