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anarmu
@anarmu
August 2022
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1-sin x =sin ^2 (П/4-x/2)
Как решить?
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Bartov17
Sinx=cos^2 (P/4-x/2)=(cosP/4cosx/2+sinP/4sinx/2)^2=(1+sinx)/2
sinx=1
x=P/2+2Pk, где К принадлежит Z
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Answers & Comments
sinx=1
x=P/2+2Pk, где К принадлежит Z