August 2022 2 8 Report
Решите уравнение: а) log1/2 (2x-4)=-2;б) log[tex] \pi [/tex] (x^2+2x+3)=log[tex] \pi [/tex] 6;
в)loga x=loga 10-loga 2: г) 1/2log2 (x-4)+1/2 log2 (2x-1)=log2 3.
Cпасибо
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  • Omsi
    спасибо.

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