Найти производную 1/2 * log(e^(2*x) + 1) - 2*arctg(e^x). Created by Koriu. algebra-ru

2 * log(e^(2*x) + 1) - 2*arctg(e^x)...

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July 2022 1 15 Report

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1/2 * log(e^(2*x) + 1) - 2*arctg(e^x)

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$y=\frac{1}{2}ln(e^{2x}+1)-2arctge^{x}\\\\y'=\frac{1}{2}\cdot \frac{2e^{2x}}{e^{2x}+1}-\frac{2e^{x}}{1+e^{2x}}=\frac{2e^{x}}{e^{2x}+1}\cdot \left (\frac{1}{2}\cdot e^{x}-1\right )$

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3x^3...

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(1+2x))^(2x-1)...

x2 3x pomogite reshit

obyasnite mne kak znaya koordinaty dvuh tochek naprimer axy i bde uznat

rasskazhite mne kak po koordinatam dvuh tochek opredelit dlinu otrezka mezhdu nimi

x...

cosx...

3x^3...

pomogite ne spravlyayus budu rada lyuboj pomoshi vse ochen slozhnoe

pomogite cheloveku s otvratitelnoj fantaziej 1 sostavit zadanie na razrabo

sintaksicheskij razbor i zapyatye rasstavit nekotorye slushateli muzyki vynimali

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