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ФаворитНогаНага
@ФаворитНогаНага
August 2022
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sin a, tg a, ctg a если:
cos a =-3/5, a =π/2 < a < 2π.
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nKrynka
Решение
sin a, tg a, ctg a если:
cos a = - 3/5, a = π/2 < a < 2π.
sina = (+-)
√(1 - cos²a) = (+-)√(1 - (-3/5)²) = (+-)√(1 - 9/25) =
√(16/25) = (+-)(4/5)
tga = sina/cosa = (-)4/5 : (-3/5) = 4/3 или tgx
= 4/5 : (-3/5) = - 4/3
ctgx = 1/tgx
ctgx = 3/4 или ctgx = - 3/4
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Answers & Comments
sin a, tg a, ctg a если:
cos a = - 3/5, a = π/2 < a < 2π.
sina = (+-) √(1 - cos²a) = (+-)√(1 - (-3/5)²) = (+-)√(1 - 9/25) =
√(16/25) = (+-)(4/5)
tga = sina/cosa = (-)4/5 : (-3/5) = 4/3 или tgx = 4/5 : (-3/5) = - 4/3
ctgx = 1/tgx
ctgx = 3/4 или ctgx = - 3/4