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fgsdfgsdfg
@fgsdfgsdfg
July 2022
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Найти cos2a и tg(a+П/4)
Если sin a = - 1/ корень 5
3П/2 < a <2П
П-пи
а-альфа
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sedinalana
Verified answer
Cosx=√1-sin²x=√(1-1/5)=√(4/5)=2/√5
cos2x=1-2sin²x=1-2*1/5=1-2/5=3/5
tgx=sinx/cosx=-1/√5:2/√5=1/2
tg(x+π/4)=(tgx+tgπ/4)/(1-tgx*π/4)=(0,5+1)/(1-0,5)=1,5/0,5=3
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Answers & Comments
Verified answer
Cosx=√1-sin²x=√(1-1/5)=√(4/5)=2/√5cos2x=1-2sin²x=1-2*1/5=1-2/5=3/5
tgx=sinx/cosx=-1/√5:2/√5=1/2
tg(x+π/4)=(tgx+tgπ/4)/(1-tgx*π/4)=(0,5+1)/(1-0,5)=1,5/0,5=3