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Daniil00000
@Daniil00000
July 2022
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Найдите cos a и tg a, если sin a = 0.6 и П/2 <a <П
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sidelnikovarim
Cos a=корень из 1-sin^2 a=1-0,36=0,64,след cos a=0,8 т.к. а во 2-ой четверти, то cosa= -0,8
tg a= sina\cosa= 0,6;(-0,8)= -0,75
10 votes
Thanks 12
Daniil00000
А как определяется четверть?
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Answers & Comments
tg a= sina\cosa= 0,6;(-0,8)= -0,75