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Anya5321
@Anya5321
July 2022
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найдите sina и tga,если известно,что cosa= 8/17 и 3п/2 <a<2п
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lidochka085
Cosa= 8/17
3п/2 <a<2п
sin a= -
√(1-cos²a)=√(-(8/17)²)=- 15/17
tg=sina /cosa =- 15/8
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Answers & Comments
sin a= - √(1-cos²a)=√(-(8/17)²)=- 15/17
tg=sina /cosa =- 15/8