Verified answer

b1=3,2,

q=1/2

Найдите

b2,

b4,

b7,

b(к+1)

b(n) = b(1) *q^{n-1}

b(2) = b(1) *q

b(2) = 3.2 * 1/2 = 1.6

b(4) = b(1) *q^{3}

b(4) = 3.2 * 1/8 = 0.4

b(7) = 3.2 * (1/2)^{6} = 3.2 * 1/64 = 0.05

b(k+1) = b(1) *q^{k}

b(k+1) = 3.2 * (1/2)^{k}