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kiritosempai
@kiritosempai
August 2022
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При каком значение k уравнение (2kx+3)/3=(k-2+x)/2 не имеет решения?
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МудрыйЕвреюшка
(2kx+3)/3=(k-2+x)/2
выражаем икс
2(2kx+3)=3(k-2+x)
4kx+6=3k-6+3x
4kx-3x=3k-12
x(4k-3)=3k-12
x=(3k-12)/(4k-3)
решений нет при 4k-3=0 => k=3/4
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Answers & Comments
выражаем икс
2(2kx+3)=3(k-2+x)
4kx+6=3k-6+3x
4kx-3x=3k-12
x(4k-3)=3k-12
x=(3k-12)/(4k-3)
решений нет при 4k-3=0 => k=3/4