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evelinavolbeat
@evelinavolbeat
June 2022
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решить уравнение cos^2x = cosx + 1
найти значения на отрезке [-5п/2; -п]
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mikael2
Cos²x-cosx-1=0 D=1+4=5
x1=1/2[1+√5] = 0.5+√5/2 >1
x2=1/2[1-√5]=0.5-√5≈-0.61
x=(-1)ⁿarcsin(0.5-√5)+πn n∈Z
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Answers & Comments
x1=1/2[1+√5] = 0.5+√5/2 >1
x2=1/2[1-√5]=0.5-√5≈-0.61
x=(-1)ⁿarcsin(0.5-√5)+πn n∈Z