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ElenVellu
@ElenVellu
July 2022
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Решить уравнение 6cos^2x -9cosx +3 =0 укажите те из его корней,которые принадлежат отрезку -5п/2;-п
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Zippert
Делаем замену cosx=t
6t^2-9t+3=0
D=81-72=9
t1/t2=9+-3/12
t1=1
t2=1/2
делаем обратную замену t=cosx
cosx=1; x=+-п/2 cosx=1/2; x=+-п/3+2Пn n
∈z
x=+-п/3+2Пn n∈z принадлежит
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Answers & Comments
6t^2-9t+3=0
D=81-72=9
t1/t2=9+-3/12
t1=1
t2=1/2
делаем обратную замену t=cosx
cosx=1; x=+-п/2 cosx=1/2; x=+-п/3+2Пn n∈z
x=+-п/3+2Пn n∈z принадлежит