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aitolkin76
@aitolkin76
September 2021
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sin2x≤1/2 помогите, кто сможет?
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Verified answer
Sin2x≤1/2
5π/6+2πn≤ 2x ≤ 13π/6+2πn, n∈Z |:2
5π/12+πn ≤ x ≤ 13π/12+πn, n∈Z
x∈[5π/12+πn; 13π/12+πn], n∈Z
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Answers & Comments
Verified answer
Sin2x≤1/25π/6+2πn≤ 2x ≤ 13π/6+2πn, n∈Z |:2
5π/12+πn ≤ x ≤ 13π/12+πn, n∈Z
x∈[5π/12+πn; 13π/12+πn], n∈Z