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msholms
@msholms
July 2022
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Cos П(х-4)/6 = 1/2 помогите решить пожалуйста!!!
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rima134
Verified answer
cospi/6(x-4)=1/2 t=pi/6(x-4) => cost=1/2 t=+-pi/3+2pin
=>pi/6(x-4)=+-pi/3+2pin умножим на 6/пи чтобы избавиться от пи/6 в левой части
pi/6*(6/pi)(x-4)=+-pi/3*6/pi+2pin*6/pi
x-4=+-2+12n => x=4+-2+12n x1=4-2+12n =2+12n
x2=4+2+12n=6+12n n(- Z
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Answers & Comments
Verified answer
cospi/6(x-4)=1/2 t=pi/6(x-4) => cost=1/2 t=+-pi/3+2pin=>pi/6(x-4)=+-pi/3+2pin умножим на 6/пи чтобы избавиться от пи/6 в левой части
pi/6*(6/pi)(x-4)=+-pi/3*6/pi+2pin*6/pi
x-4=+-2+12n => x=4+-2+12n x1=4-2+12n =2+12n
x2=4+2+12n=6+12n n(- Z