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RichB
@RichB
August 2022
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f(x) = (sin²(π/2 -x) - 1) / ( cos(3π/2 + x) )
f ' (x) = 1/2
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Vasilisagr
F(x)=(cos^2x-1)/sinx
F(x)=-sin^2x/sinx
F(x)=-sinx
F"(x)=-cosx
-cosx=1/2cos x=-1/2
х=
+-
(п-arccos-1/2)+2пn
х=+-п -п/3+2пn
х=+-2п/3+2пn,где n-цел.числа
2 votes
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Answers & Comments
F(x)=-sin^2x/sinx
F(x)=-sinx
F"(x)=-cosx
-cosx=1/2cos x=-1/2
х=+-(п-arccos-1/2)+2пn
х=+-п -п/3+2пn
х=+-2п/3+2пn,где n-цел.числа