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barkalayairina
@barkalayairina
August 2022
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sin^4x-cos^4x=1/2
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sedinalana
Verified answer
(sin²x-cos²x)(sin²x+cos²x)=1/2
-cos2x*1=1/2
cos2x=-1/2
2x=+-2π/3+2πn,n∈z
x=+-π/3+πn,n∈z
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Verified answer
(sin²x-cos²x)(sin²x+cos²x)=1/2-cos2x*1=1/2
cos2x=-1/2
2x=+-2π/3+2πn,n∈z
x=+-π/3+πn,n∈z