Home
О нас
Products
Services
Регистрация
Войти
Поиск
dmitrijfrol201
@dmitrijfrol201
July 2022
1
8
Report
2 примера на предел
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sangers1959
Verified answer
5.8.
lim(x→∞) (5x²-4x+2)/(4x²+2x-5).
lim(x→∞) (5-4/x+2/x²)/(4+2/x-5/x²)=(5-0+0)/(4+0-0)=5/4=1¹/₄.
6.8.
lim(x→4) -(2x²-9x+4)/(√(5-x)-√(x-3))
2x²-9x+4=2x²-8x-(x-4)=2x*(x-4)-(x-4)=(x-4)*(2x-1)=2*(x-4)*(x-0,5)
Умножим числитель и знаменатель на (√(5-х)+√(х-3)):
lim(x→4) -(2*(x-4)*(x-0,5)/((√(5-x))²-(√(x-3))²)=
=lim(x→4) -(2*(x-4)*(x-0,5))/(8-2x)=
=lim(x→4) -(2*(x-4)*(x-0,5))*(√(5-x)+√(x-3))/(-2*x-4)=
=lim(x→4) (x-0,5)*(√(5-x)+√(x-3))=(4-0,5)*(√1+√1)=3,5*2=7.
0 votes
Thanks 0
More Questions From This User
See All
dmitrijfrol201
August 2022 | 0 Ответы
pomogite s zadachkoj pozhalujstad3eaf7bf7cd3bc05398d194011b54c79 19797
Answer
dmitrijfrol201
August 2022 | 0 Ответы
vypolnite dejstvie 1 i
Answer
dmitrijfrol201
August 2022 | 0 Ответы
vychislite proizvodnye5b14764c61a41c2caa118d196cf5583a 40266
Answer
dmitrijfrol201
August 2022 | 0 Ответы
summa cifr chisla s 3333 333 raza 2 ravna
Answer
dmitrijfrol201
August 2022 | 0 Ответы
pomogite pozhalujsta funkciya fx opredelena na vsej chislovoj osi i dlya lyubyh x
Answer
dmitrijfrol201
August 2022 | 0 Ответы
nuzhna pomosh pust x0 y0 z0 reshenie sistemy uravnenij x2y2 2z2
Answer
dmitrijfrol201
August 2022 | 0 Ответы
pomogite pozhalujsta esli pryamye yx3 y x5 i ykx peresekayutsya v odnoj to
Answer
dmitrijfrol201
August 2022 | 0 Ответы
sokratite drob pozhalujstaa9cdd647a0999b983b232a7d72b72671 39320
Answer
dmitrijfrol201
August 2022 | 0 Ответы
tex]...
Answer
dmitrijfrol201
August 2022 | 0 Ответы
tex]...
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2 примера на предел..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
5.8.lim(x→∞) (5x²-4x+2)/(4x²+2x-5).
lim(x→∞) (5-4/x+2/x²)/(4+2/x-5/x²)=(5-0+0)/(4+0-0)=5/4=1¹/₄.
6.8.
lim(x→4) -(2x²-9x+4)/(√(5-x)-√(x-3))
2x²-9x+4=2x²-8x-(x-4)=2x*(x-4)-(x-4)=(x-4)*(2x-1)=2*(x-4)*(x-0,5)
Умножим числитель и знаменатель на (√(5-х)+√(х-3)):
lim(x→4) -(2*(x-4)*(x-0,5)/((√(5-x))²-(√(x-3))²)=
=lim(x→4) -(2*(x-4)*(x-0,5))/(8-2x)=
=lim(x→4) -(2*(x-4)*(x-0,5))*(√(5-x)+√(x-3))/(-2*x-4)=
=lim(x→4) (x-0,5)*(√(5-x)+√(x-3))=(4-0,5)*(√1+√1)=3,5*2=7.