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marinapetrova1
@marinapetrova1
August 2022
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найдите 17 cos альфа если sin альфа -8/17 и П<альфа<3П/2
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martnatalya
Cos²α=1 - sin²α = 1 - 64/289 = 225/289
α - в III координатной четверти, cos в ней отрицательный
cosα= - √225/289 = - 15/17
17 cos α = 17· (-15/17) = - 15
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Answers & Comments
α - в III координатной четверти, cos в ней отрицательный
cosα= - √225/289 = - 15/17
17 cos α = 17· (-15/17) = - 15