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AnnHarina
@AnnHarina
August 2022
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sin4x+sin3x+sin2x=0
(2sin (4x+3x)/2) * (cos (4x-3x)/2) + sin2x
что дальше? заранее спасибо
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XGuruX
Проще вот так:
sin4x+sin2x+sin3x=2sin3xcosx+sin3x=0
sin3x(2cosx+1)=0
sin3x=0
3x=pin
x=pin/3 n e z
cosx=-1/2
x=+-2pi/3 + 2pin n e z
1 votes
Thanks 1
AnnHarina
sin3x(2cosx+1)=0 почему вы умножаете sin3x на скобку? а не +
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Answers & Comments
sin4x+sin2x+sin3x=2sin3xcosx+sin3x=0
sin3x(2cosx+1)=0
sin3x=0
3x=pin
x=pin/3 n e z
cosx=-1/2
x=+-2pi/3 + 2pin n e z