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ДидараКусманова11
@ДидараКусманова11
July 2022
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помогите пожалуйстааа
cosx+cos^2x=1/2-sin^2x
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Dимасuk
Verified answer
Cosx + cos²x = 1/2 - sin²x
cosx + cos²x + sin²x = 1/2
cosx + 1 = 1/2
cosx = -1/2
x = ±arccos(-1/2) + 2πn, n ∈ Z.
x = ±2π/3 + 2πn, n ∈ Z.
Ответ: х = ±2π/3 + 2πn, n ∈ Z.
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Answers & Comments
Verified answer
Cosx + cos²x = 1/2 - sin²xcosx + cos²x + sin²x = 1/2
cosx + 1 = 1/2
cosx = -1/2
x = ±arccos(-1/2) + 2πn, n ∈ Z.
x = ±2π/3 + 2πn, n ∈ Z.
Ответ: х = ±2π/3 + 2πn, n ∈ Z.