2-sin2x+cos4x=0 помогите пожалуйста
cos²2x = 1+cos4x/2
cos4x = 2cos²2x-1
2- sin2x + 2(1-sin²2x) - 1 = 0
2 - sin2x + 2 - 2sin²2x - 1 = 0
2sin²2x + sin2x - 3 = 0
sin2x = a
2a² + a - 3 = 0
a1 = -6/4 не подходит
а2 = 1
sin2x = 1
2x = π/2 + 2πn
x = π/4 + πn
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Answers & Comments
cos²2x = 1+cos4x/2
cos4x = 2cos²2x-1
2- sin2x + 2(1-sin²2x) - 1 = 0
2 - sin2x + 2 - 2sin²2x - 1 = 0
2sin²2x + sin2x - 3 = 0
sin2x = a
2a² + a - 3 = 0
a1 = -6/4 не подходит
а2 = 1
sin2x = 1
2x = π/2 + 2πn
x = π/4 + πn