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pokutyashaaa
@pokutyashaaa
July 2022
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распишите пожалуйста sqrt(tgx)+sqrt(ctgx)=5/2
sqrt - корень из
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Gerren
√tgx+√ctgx=5/2
√tgx+√(1/tgx)=5/2
√tgx=a
a+1/a=5/2 умножим на 2a
2a^2+2=5a
2a^2-5a+2=0
D=25-4*2*2=25-16=9
a1=(5+3)/4=2
a2=(5-3)/4=2/4=1/2
√tgx=2
tgx=4
x=arctg4+pi*n n∈Z
√tgx=1/2
tgx=1/4
x=arctg(1/4)+pi*k k∈Z
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pokutyashaaa
спасибо большое)
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Answers & Comments
√tgx+√(1/tgx)=5/2
√tgx=a
a+1/a=5/2 умножим на 2a
2a^2+2=5a
2a^2-5a+2=0
D=25-4*2*2=25-16=9
a1=(5+3)/4=2
a2=(5-3)/4=2/4=1/2
√tgx=2
tgx=4
x=arctg4+pi*n n∈Z
√tgx=1/2
tgx=1/4
x=arctg(1/4)+pi*k k∈Z