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July 2022
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Вычислите значение cos^2 α/2 угла α между векторами x= 2i + 5j - k и y=i - j - 3k. ( все буквы в задании (x;i;j;k;y) вектора)
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sedinalana
Verified answer
X{2;5;-1} y{1;-1;-3}
cosa=(2*1-1*5-1*(-3))/(√(4+25+1)*√(1+1+9))=(2-5+3)/(√30*√11)=0
a=π/2
a/2=π/4
cosa/2=cosπ/4=√2/2
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Verified answer
X{2;5;-1} y{1;-1;-3}cosa=(2*1-1*5-1*(-3))/(√(4+25+1)*√(1+1+9))=(2-5+3)/(√30*√11)=0
a=π/2
a/2=π/4
cosa/2=cosπ/4=√2/2