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Диас123123
@Диас123123
July 2022
1
5
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2 вариант 3-4 задачи решите пж с подробностями
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sedinalana
3
cos4x=cos6x
cos4x-cos6x=0
2sinx*sin5x=0
sinx=0⇒x=πk,k∈z
sin5x=0⇒5x=πk⇒x=πk/5,k∈z
Ответ x=πk/5,k∈z
4
f`(x)=x³-2x²-3x=x(x²-2x-3)=x(x-3)(x+1)=0
x=0 x=3 x=-1
_ + _ +
----------(-1)------------(0)------------(3)-----
min max min
ymin=1/4+2/3-3/2+2=(3+8-18+24)/12=17/12
ymax=2
ymin=81/4-18-27/2+2=(81-72-54+8)/4=-37/4
2 votes
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Answers & Comments
cos4x=cos6x
cos4x-cos6x=0
2sinx*sin5x=0
sinx=0⇒x=πk,k∈z
sin5x=0⇒5x=πk⇒x=πk/5,k∈z
Ответ x=πk/5,k∈z
4
f`(x)=x³-2x²-3x=x(x²-2x-3)=x(x-3)(x+1)=0
x=0 x=3 x=-1
_ + _ +
----------(-1)------------(0)------------(3)-----
min max min
ymin=1/4+2/3-3/2+2=(3+8-18+24)/12=17/12
ymax=2
ymin=81/4-18-27/2+2=(81-72-54+8)/4=-37/4