Home
О нас
Products
Services
Регистрация
Войти
Поиск
Диас123123
@Диас123123
July 2022
1
6
Report
2 вариант 3-4 задачи решите пж с подробностями
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
3
cos4x=cos6x
cos4x-cos6x=0
2sinx*sin5x=0
sinx=0⇒x=πk,k∈z
sin5x=0⇒5x=πk⇒x=πk/5,k∈z
Ответ x=πk/5,k∈z
4
f`(x)=x³-2x²-3x=x(x²-2x-3)=x(x-3)(x+1)=0
x=0 x=3 x=-1
_ + _ +
----------(-1)------------(0)------------(3)-----
min max min
ymin=1/4+2/3-3/2+2=(3+8-18+24)/12=17/12
ymax=2
ymin=81/4-18-27/2+2=(81-72-54+8)/4=-37/4
2 votes
Thanks 1
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "2 вариант 3-4 задачи решите пж с подробностями..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
cos4x=cos6x
cos4x-cos6x=0
2sinx*sin5x=0
sinx=0⇒x=πk,k∈z
sin5x=0⇒5x=πk⇒x=πk/5,k∈z
Ответ x=πk/5,k∈z
4
f`(x)=x³-2x²-3x=x(x²-2x-3)=x(x-3)(x+1)=0
x=0 x=3 x=-1
_ + _ +
----------(-1)------------(0)------------(3)-----
min max min
ymin=1/4+2/3-3/2+2=(3+8-18+24)/12=17/12
ymax=2
ymin=81/4-18-27/2+2=(81-72-54+8)/4=-37/4