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010ШАХ010
@010ШАХ010
July 2022
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Дано: sin(4π+t)=3/5, 0<t<π/2. Вычислите tg(π-t).
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010ÃããÃ010
Verified answer
Sin(4π+t)=3/5,
0<t<π/2
tg(π-t)-?
sin(4π+t)=sint=3/5
tg(π-t)=-tgt
-tgt=-sint/cost
cos=√1-sin²t=√1-9/25=√16/25
cost=4/5
-tgt=-3/5*5/4=-3/4
4 votes
Thanks 5
Universalka
Verified answer
Sin(4π + t) = 3/5
Sint = 3/5
Cost = + - √(1 - Sin²t)
Так как t - угол первой четверти, то
Cost = √(1 - Sin²t) = √( 1 - 9/25) = √16/25 = 4/5
tg(π - t) = - tgt = - Sint/Cost = - 3/5 : 4/5 = - 3/4 = - 0,75
3 votes
Thanks 6
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Answers & Comments
Verified answer
Sin(4π+t)=3/5,0<t<π/2
tg(π-t)-?
sin(4π+t)=sint=3/5
tg(π-t)=-tgt
-tgt=-sint/cost
cos=√1-sin²t=√1-9/25=√16/25
cost=4/5
-tgt=-3/5*5/4=-3/4
Verified answer
Sin(4π + t) = 3/5Sint = 3/5
Cost = + - √(1 - Sin²t)
Так как t - угол первой четверти, то
Cost = √(1 - Sin²t) = √( 1 - 9/25) = √16/25 = 4/5
tg(π - t) = - tgt = - Sint/Cost = - 3/5 : 4/5 = - 3/4 = - 0,75