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Kolya2002Neznaika
@Kolya2002Neznaika
August 2022
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CРОЧНО!!!20 БАЛЛОВ
1.Решите неравенство 14х-(х+2)²/4<х²-1
2.Найдите область определения функции y=√(x+6)(7-2x)/x
3.Решите неравенство (x-4)²/2-x ≥ 0
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diedinahead
14х-(х+2)²/4<х²-1
14х-(х+2)²<4х²-4
14x-(x²+4x+4)<4x²-4
14x-x²-4x-4<4x²-4
3x²+10x<0
x(3x+10)<0
3x=10
x=3
⅓
x=0
0 votes
Thanks 1
diedinahead
(x-4)²/2-x ≥ 0
Kolya2002Neznaika
Это где
Kolya2002Neznaika
А остальное не решишь?
Kolya2002Neznaika
Реши пож
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Answers & Comments
14х-(х+2)²<4х²-4
14x-(x²+4x+4)<4x²-4
14x-x²-4x-4<4x²-4
3x²+10x<0
x(3x+10)<0
3x=10
x=3⅓
x=0