2sin^2x- корень из 3cos(pi/2 - x) =0. Created by roma555. algebra-ru

2 - x) =0...

roma555 @roma555

July 2022 1 16 Report

2sin^2x- корень из 3cos(pi/2 - x) =0

Answers & Comments

emerald0101

Verified answer

$2sin^2x- \sqrt{3}cos( \frac{ \pi }{2}-x)=0;$
$2sin^2x- \sqrt{3}sinx=0; sinx(2sinx- \sqrt{3}) =0;$
$sinx=0;x= \pi n,n \in Z;$
$2sinx- \sqrt{3}=0; 2sinx= \sqrt{3};sinx= \frac{\sqrt{3}}{2};x=(-1)^n \frac{ \pi }{3}+ \pi n,n \in Z;$

17 votes Thanks 29

Answers & Comments

Verified answer

Helpful Links

Helpful Social