2sin^2x- корень из 3cos(pi/2 - x) =0. Created by roma555. algebra-ru

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roma555 @roma555

July 2022 1 17 Report

2sin^2x- корень из 3cos(pi/2 - x) =0

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emerald0101

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$2sin^2x- \sqrt{3}cos( \frac{ \pi }{2}-x)=0;$
$2sin^2x- \sqrt{3}sinx=0; sinx(2sinx- \sqrt{3}) =0;$
$sinx=0;x= \pi n,n \in Z;$
$2sinx- \sqrt{3}=0; 2sinx= \sqrt{3};sinx= \frac{\sqrt{3}}{2};x=(-1)^n \frac{ \pi }{3}+ \pi n,n \in Z;$

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