Ответ:
1)f(x) = 4x³-12x+5
f(0)=4•0³-12•0+5
f(0)=4•0-0+5
f(0)=0+5
f(0)=5
2)f(x)=-9/2-x
f(0)=-9/2-x
X€0
3)f(x)=2x³-12x-1
f(0)=2•0³-12•0-1
f(0)=2•0-0-1
f(0)=0-1
f(0)=-1
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Ответ:
1)f(x) = 4x³-12x+5
f(0)=4•0³-12•0+5
f(0)=4•0-0+5
f(0)=0+5
f(0)=5
2)f(x)=-9/2-x
f(0)=-9/2-x
X€0
3)f(x)=2x³-12x-1
f(0)=2•0³-12•0-1
f(0)=2•0-0-1
f(0)=0-1
f(0)=-1