( sin(2pi - x) tg(3pi/2 - x) - cos(x- pi) - sin(x-pi))^2 + cos^2(pi - x)
(sin(2pi-x)tg(3pi/2--x)-cos(x-pi)-sin(x-pi))^2 + cos^2(pi-x) =
= (-sinxctgx -(-cosx)-(-sinx))^2+cos^2x = (-sinxcosx/sinx+cosx+sinx)^2 + cos^2x =
= (-cosx+cosx+sinx)^2 + cos^2x = sin^2x + cos^2x = 1
Ответ. 1
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Answers & Comments
(sin(2pi-x)tg(3pi/2--x)-cos(x-pi)-sin(x-pi))^2 + cos^2(pi-x) =
= (-sinxctgx -(-cosx)-(-sinx))^2+cos^2x = (-sinxcosx/sinx+cosx+sinx)^2 + cos^2x =
= (-cosx+cosx+sinx)^2 + cos^2x = sin^2x + cos^2x = 1
Ответ. 1