July 2021 0 10 Report
Помогите пожалуйста. Найдите корни уравнения на заданном промежутке: sinx=-(корень2)/2, x принадлежит [-п;2п]
Please enter comments
Please enter your name.
Please enter the correct email address.
You must agree before submitting.
More Questions From This User See All
pomogite pozhalujsta najti proizvodnuyufxsinxcosxcos2x
Answer
pomogite pozhalujsta zakon dvizheniya nekotoroj tochki po pryamoj zadaetsya formuloj
Answer
pomogite pozhalujsta najdite proizvodnuyu funkciiykoren iz x8x 10 ykoren
Answer
pozhalujsta pomogite srochno a to ya uzhe zaputalasdabc tetraedr ugly dbadb
Answer
2-sin^2(2x)...
Answer
pomogite reshit uravnenie sin12xsin4x0
Answer
4...
Answer
pomogite pozhalujsta najdite proizvodnuyu funkciiyx8x 10 y xx42
Answer
pomogite pozhalujsta najdite proizvodnuyu funkcii yxcosx ykoren iz xsinx
Answer

Helpful Links

Helpful Social

Copyright © 2024 SCHOLAR.TIPS - All rights reserved.