Ответ:
2 - x)(2x + 1) i (x - 2)(x + 2)
( 2 - x ) x ( 2x + 1 )
(x-2)×(x+2)
2 - x ) x ( 2x + 1 ) = ( 2 - x ) x ( 2x + 1 )
( x - 2 ) x ( x + 2 ) = ( x - 2 ) x ( x + 2 )
( 2 - x ) x ( 2x + 1 ) × ( x - 2 ) x ( x + 2 )
7x³ - 2x4 + 10x² - 4x - 4x³ - 8x - 8
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Verified answer
Ответ:
2 - x)(2x + 1) i (x - 2)(x + 2)
( 2 - x ) x ( 2x + 1 )
(x-2)×(x+2)
2 - x ) x ( 2x + 1 ) = ( 2 - x ) x ( 2x + 1 )
( x - 2 ) x ( x + 2 ) = ( x - 2 ) x ( x + 2 )
( 2 - x ) x ( 2x + 1 ) × ( x - 2 ) x ( x + 2 )
7x³ - 2x4 + 10x² - 4x - 4x³ - 8x - 8