помогите решить sin2x = cos(π/2 - x)
sin2x = 2sin x*cos x
cos(π/2 - x) = sin x
2sin x*cos x = sin x - отсюда следует cos x = 1/2 х = 2kπ +- π/3.
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sin2x = 2sin x*cos x
cos(π/2 - x) = sin x
2sin x*cos x = sin x - отсюда следует cos x = 1/2 х = 2kπ +- π/3.