2 задание,алгебра 10 класс Прошу!!!. Created by nikolee. algebra-ru

2 задание,алгебра 10 класс Прошу!!!...

nikolee @nikolee

July 2022 1 11 Report

2 задание,алгебра 10 класс
Прошу!!!

Answers & Comments

sangers1959

Verified answer

Ответ:

Объяснение:

$2.\\ sin\frac{x}{3} =-\frac{1}{2} ; [0;3\pi ]\\\frac{x}{3}=\frac{7\pi }{6} +2\pi n|*3\\x_{1} =\frac{7\pi }{2} +6\pi n=\frac{7\pi }{2}.\\ \frac{x}{3}= \frac{11\pi }{6}+2\pi n|*3\\x_{2} =\frac{11\pi }{2}+6\pi n=\frac{11\pi }{2}. \\x_{1}=\frac{7\pi }{2};x_{2} =\frac{11\pi }{2}.$

0 votes Thanks 1

Answers & Comments

Verified answer

Helpful Links

Helpful Social