2 задания на синус и косинус! Прошу помощи :)
1)=2√3 cos^2 (5П/12)-√3=√3(2 cos^2 (5П/12)-1)= √3cos 5П/6= - √3 * √3/2=-3/2
2)= √3-2 √3 sin^2 ( 5П/12)= √3(1-2 sin^2 ( 5П/12) )= √3 cos 5П/6= - √3 * √3/2=-3/2
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1)=2√3 cos^2 (5П/12)-√3=√3(2 cos^2 (5П/12)-1)= √3cos 5П/6= - √3 * √3/2=-3/2
2)= √3-2 √3 sin^2 ( 5П/12)= √3(1-2 sin^2 ( 5П/12) )= √3 cos 5П/6= - √3 * √3/2=-3/2