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Unbroken
@Unbroken
August 2022
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sin^2x-cos^2x=1/2
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tseluyko58
Verified answer
Sin²x-cos²x=1/2
-cos2x=1/2
cos2x=-1/2
2x=+-arccos(-1/2)+2πn
x=+-π/3+πn
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Answers & Comments
Verified answer
Sin²x-cos²x=1/2-cos2x=1/2
cos2x=-1/2
2x=+-arccos(-1/2)+2πn
x=+-π/3+πn