Ответ:

[tex][-2\frac{7}{9};1\frac{2}{3}][/tex]

Пошаговое объяснение:

[tex]|5+9x|\leq 20\\\\-20\leq 5+9x\leq 20\\\\-20-5\leq 9x\leq 20-5\\\\-25\leq 9x\leq 15\; \; |:9\\\\-25:9\leq x\leq 15:9\\\\-2\frac{7}{9}\leq x\leq 1\frac{2}{3}\\\\x\in[-2\frac{7}{9};1\frac{2}{3}][/tex]