Ответ:

(1/5)²

(1/5)³

1/х

(1/АБ)⁵

(1/7)³

(1/б)⁴⁰

(1/а+б)⁶

(1/х-у)¹⁰

Verified answer

[tex] {5}^{ - 2} = \frac{1}{ {5}^{2} } = \frac{1}{25} [/tex]

[tex] {5}^{ - 3} = \frac{1}{ {5}^{3} } = \frac{1}{125} [/tex]

[tex] {x}^{ - 1} = \frac{1}{x} [/tex]

[tex] {(ab)}^{ - 5} = \frac{1}{ {(ab)}^{5} } = \frac{1}{ {a}^{5} {b}^{5} } [/tex]

[tex] {7}^{ - 3} = \frac{1}{ {7}^{3} } = \frac{1}{343} [/tex]

[tex] {b}^{ - 40} = \frac{1}{ {b}^{40} } [/tex]

[tex] {(a + b)}^{ - 6} = \frac{1}{ {(a + b)}^{6} } [/tex]

[tex] {(x - y)}^{ - 10} = \frac{1}{ {(x - y)}^{10} } [/tex]