[tex]\displaystyle -\frac{15+3x}{42}=\frac{-3x-19}{46}\\ \\-\frac{3(5+x)}{42}=\frac{-3x-19}{46}\\ \\-\frac{5+x}{14}=\frac{-3x-19}{46}\\ \\-46(5+x)=14(-3x-19)\\ -230-46x=-42x-266\\ -46x+42x=-266+230\\ -4x=-36\\x=9[/tex]
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[tex]\displaystyle -\frac{15+3x}{42}=\frac{-3x-19}{46}\\ \\-\frac{3(5+x)}{42}=\frac{-3x-19}{46}\\ \\-\frac{5+x}{14}=\frac{-3x-19}{46}\\ \\-46(5+x)=14(-3x-19)\\ -230-46x=-42x-266\\ -46x+42x=-266+230\\ -4x=-36\\x=9[/tex]