Ответ:
-1 -a
Объяснение:
[tex]\frac{2a}{a^{2}-1 } (\frac{1}{1-a^{2} }-\frac{1}{1+2a+a^{2} } ) \\\frac{2a}{(a-1)(a+1)} :(\frac{1}{(1-a)(1+a)}-\frac{1}{(1+a)^{2} }} )\\\frac{2a}{(a-1)(a+1)}:\frac{1+a-(1-a)}{(1-a)(1+a)^{2}}\\\frac{2a}{(a-1)(a+1)}*\frac{2a}{(1-a)(1+a)^{2}}\\\frac{1}{a-1}*(-(a-1))(1+a)\\-(1+a)\\-1 -a[/tex]
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Answers & Comments
Ответ:
-1 -a
Объяснение:
[tex]\frac{2a}{a^{2}-1 } (\frac{1}{1-a^{2} }-\frac{1}{1+2a+a^{2} } ) \\\frac{2a}{(a-1)(a+1)} :(\frac{1}{(1-a)(1+a)}-\frac{1}{(1+a)^{2} }} )\\\frac{2a}{(a-1)(a+1)}:\frac{1+a-(1-a)}{(1-a)(1+a)^{2}}\\\frac{2a}{(a-1)(a+1)}*\frac{2a}{(1-a)(1+a)^{2}}\\\frac{1}{a-1}*(-(a-1))(1+a)\\-(1+a)\\-1 -a[/tex]