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Ответ:

[tex]1) \frac{ \sqrt{6} - \sqrt{2} }{ \sqrt{8} } = \frac{ \sqrt{3} \times \sqrt{2} - \sqrt{2} }{2 \sqrt{2} } = \frac{ \sqrt{3} - 1}{2} [/tex]

[tex]2) \frac{ \sqrt{6} + \sqrt{15} }{ \sqrt{8} + \sqrt{20} } = \frac{ \sqrt{3} \times \sqrt{2} + \sqrt{3} \times \sqrt{5} }{2 \sqrt{2} + 2 \sqrt{5} } = \frac{ \sqrt{3} ( \sqrt{2} + \sqrt{5} )}{2( \sqrt{2} + \sqrt{5} )} = \frac{ \sqrt{3} }{2} [/tex]

[tex]3) \frac{10 - 2 \sqrt{5} }{ \sqrt{20} - 2 } = \frac{2(5 - \sqrt{5}) }{2( \sqrt{5} - 1)} = \frac{2 \sqrt{5}( \sqrt{5} - 1) }{2( \sqrt{5} - 1) } = \frac{2 \sqrt{5} }{2} = \sqrt{5} [/tex]

[tex]4) \frac{4 + 2 \sqrt{2} }{ \sqrt{8} + 2 } = \frac{2 \sqrt{2} ( \sqrt{2} + 1)}{2( \sqrt{2} + 1) } = \frac{2 \sqrt{2} }{2} = \sqrt{2} [/tex]