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zalivakoyana15
@zalivakoyana15
August 2022
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20 баллов,кто поможет)
разложите на множители:
1. 9-(2с-1)* в квадрате *
2. (а+в+2)(а+в)-(а-в)* в квадрате *+1
3. (х*в квадрате*+1)* в квадрате *-4х* в квадрате *
4. 1-(8а-3)* в квадрате *
5. 25+40а* в кубе *+ 16а* в 6 степени *
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oganesbagoyan
Verified answer
1. (3 -2c+1)(3+2c -1) ;
2. (a+b+2)(a+b) -(a-b)² +1 =(a+b)² +2(a+b) -(a-b)² +1 =
2(a+b) +1 +
(a+b)² -(a-b)² =2(a+b) +1 +4ab ???
3. (x² +1)² - 4x² =(x² +1 -2x)(x² +1 +2x) =(x-1)²(x+1)² || (x² -1)
² ||
(
x² )² +2*x²*1 +1² - 4x² =
(
x² )² -2*x²*1 = (x² -1)
² .
4. 1 -(8a -3)
² =(1 -8a+3)(1+8a - 3) =(4 - 8a)(8a -2) =8(1-2a)(4a -1).
5. 25 +40a³ +16a
⁶ =5
² +2*5*4a³ +(4a³)² =(5 +4a³)² .
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Answers & Comments
Verified answer
1. (3 -2c+1)(3+2c -1) ;2. (a+b+2)(a+b) -(a-b)² +1 =(a+b)² +2(a+b) -(a-b)² +1 =
2(a+b) +1 + (a+b)² -(a-b)² =2(a+b) +1 +4ab ???
3. (x² +1)² - 4x² =(x² +1 -2x)(x² +1 +2x) =(x-1)²(x+1)² || (x² -1)² ||
(x² )² +2*x²*1 +1² - 4x² = (x² )² -2*x²*1 = (x² -1)² .
4. 1 -(8a -3)² =(1 -8a+3)(1+8a - 3) =(4 - 8a)(8a -2) =8(1-2a)(4a -1).
5. 25 +40a³ +16a⁶ =5² +2*5*4a³ +(4a³)² =(5 +4a³)² .