Ответ:
Объяснение:
В - 3 .
1 . а) 6ас³/( c² - a²) * ( a + c )/4c² = [ 6ac³( c + a )]/[ 4c²( c - a ) ( c + a ) ] =3ac/2(c - a ) ;
б) ( 1 + a²/( 2a + 1 ) ) : ( a + 1 )/( 2a + 1 ) - a = 1 .
1) 1 + a²/( 2a + 1 ) = ( 2a + 1 + a²)/( 2a + 1 ) = ( a + 1 )²/( 2a + 1 ) ;
2) ( a + 1 )²/( 2a + 1 ) : ( a + 1 )/( 2a + 1 ) = ( a + 1 )²/( 2a + 1 ) * ( 2a + 1 )/ ( a + 1 ) = a + 1 ;
3) a + 1 - a = 1 .
2 . a ) 15/x + 17/2x = 1/2 ;
47/2x = 1/2 ;
2x = 2 * 47 ;
x = 47 . В - дь : x = 47 .
б ) ( 2z² - 7z + 3 ) / ( 2z - 1 ) = 1 + z ; ( z ≠ 1/2 ) ;
2z² - 7z + 3 = ( z + 1 )( 2z - 1 ) ;
2z² - 7z + 3 = 2z² - z + 2z - 1 ;
- 7z - z = - 1 - 3 ;
- 8z = - 4 ;
z = - 4 : ( - 8 ) ;
z = 1/2 . В - дь : z = 1/2 .
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Объяснение:
В - 3 .
1 . а) 6ас³/( c² - a²) * ( a + c )/4c² = [ 6ac³( c + a )]/[ 4c²( c - a ) ( c + a ) ] =3ac/2(c - a ) ;
б) ( 1 + a²/( 2a + 1 ) ) : ( a + 1 )/( 2a + 1 ) - a = 1 .
1) 1 + a²/( 2a + 1 ) = ( 2a + 1 + a²)/( 2a + 1 ) = ( a + 1 )²/( 2a + 1 ) ;
2) ( a + 1 )²/( 2a + 1 ) : ( a + 1 )/( 2a + 1 ) = ( a + 1 )²/( 2a + 1 ) * ( 2a + 1 )/ ( a + 1 ) = a + 1 ;
3) a + 1 - a = 1 .
2 . a ) 15/x + 17/2x = 1/2 ;
47/2x = 1/2 ;
2x = 2 * 47 ;
x = 47 . В - дь : x = 47 .
б ) ( 2z² - 7z + 3 ) / ( 2z - 1 ) = 1 + z ; ( z ≠ 1/2 ) ;
2z² - 7z + 3 = ( z + 1 )( 2z - 1 ) ;
2z² - 7z + 3 = 2z² - z + 2z - 1 ;
- 7z - z = - 1 - 3 ;
- 8z = - 4 ;
z = - 4 : ( - 8 ) ;
z = 1/2 . В - дь : z = 1/2 .