Объяснение:
Дано:
m1=200г
w1=15%
w2=10%
m(H2O)-?
w2= m1×w1/(m1+m(H2O))
0.1=(200•0.15)/(200+x)
0.1(200+x)=200•0.15
20+0.1x=30
0.1x=10
x=100г води
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Verified answer
Объяснение:
Дано:
m1=200г
w1=15%
w2=10%
m(H2O)-?
w2= m1×w1/(m1+m(H2O))
0.1=(200•0.15)/(200+x)
0.1(200+x)=200•0.15
20+0.1x=30
0.1x=10
x=100г води