Определите при каком значении а верно равенство 148:(8a-3)+6=2003/2003. Created by Dasha200270. matematika-ru

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Dasha200270 @Dasha200270

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Определите при каком значении а верно равенство 148:(8a-3)+6=2003/2003

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dtnth

Verified answer

$148:(8a-3)+6=\frac{2003}{2003}$
$148:(8a-3)+6=1$
$148:(8a-3)=1-6$
$148:(8a-3)=-5$
$8a-3=148:(-5)$
$8a-3=-29.6$
$8a=-29.6+3$
$8a=-26.6$
$a=-26.6:8$
$a=-3.325$

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